Combine category and taxonomy

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This topic contains 2 replies, has 2 voices, and was last updated by lorenz lorenz 3 years, 8 months ago.

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  • #20704
    lorenz
    lorenz
    Participant

    I have a category named “betreuung”
    And I have a taxanomy named “betreuung”
    So, when I search for “betreuung” I get two (identical) lines for the results. See attached screen shot (first 2 lines):
    – Betreuung (119)
    – Betreuung (27)

    My customer, however, only wants so see one line;
    – Betreuung (146)

    I tried hard to solve this but did not succeed.

    Can you please help me with this?

    Thanks a lot,

    Regards
    Lorenz
    (Germany)

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    #20712
    Ernest Marcinko
    Ernest Marcinko
    Keymaster

    Hi!

    Well, this could get really difficult, as each taxonomy term is probably linking to a different location. I have put together small code snipptet, that will try to group the terms by name during the post process.
    Try adding this custom code to the functions.php in your theme/child theme directory (copy from line 3 only!). Before editing, please make sure to have a full site back-up just in case!

    add_filter('asp_results', 'asp_group_terms', 10, 1);
    function asp_group_terms($results) {
      $terms = array();
      $terms_occurence = array();
      $new_results = array();
      
      foreach($results as $k=>&$r) {
        if ( isset($r->taxonomy) ) {
          preg_match('/^(.*?)\((.*?)\)/', $r->title, $m);
          if ( isset($m[1], $m[2]) ) {
            $terms[$m[1]] = isset( $terms[$m[1]] ) ? $terms[$m[1]] + $m[2] : $m[2];
          }
        }
      }
      foreach($results as $k=>&$r) {
        if ( isset($r->taxonomy) ) {
          preg_match('/^(.*?)\((.*?)\)/', $r->title, $m);
          if ( isset($m[1], $m[2]) ) {
            // Already occured once, reset it
            if ( !isset($terms_occurence[$m[1]]) ) {
              $r->title = $m[1] . '(' . $terms[$m[1]] . ')';
              $new_results[] = $r;
              $terms_occurence[$m[1]] = true;  
            }       
          } else {
            $new_results[] = $r;
          }
        } else {
          $new_results[] = $r;
        }
      }
      
      return $new_results;
    }

    Please note, that this might not work in each and every case though.

    Best,
    Ernest Marcinko

    If you like my products, don't forget to rate them on codecanyon :)


    #20715
    lorenz
    lorenz
    Participant

    Thank you so much for your support. This is much more support than I have expected!
    I will let you know, how it works.

    Thanks,

    Lorenz
    (Germany)

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