Home › Forums › Product Support Forums › Ajax Search Pro for WordPress Support › PHP Notice with the new update
This topic contains 2 replies, has 2 voices, and was last updated by Jacques Letesson 7 years, 8 months ago.
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- December 30, 2015 at 12:27 pm #7196
Hi there,
Since the new update, I receive several php notices related to Ajax Search Pro :
Notice: Undefined index: SERVER_PORT in /home/restofra/public_html/wp-content/plugins/ajax-search-pro/functions.php on line 183 Notice: Undefined index: SERVER_NAME in /home/restofra/public_html/wp-content/plugins/ajax-search-pro/functions.php on line 184 Notice: Undefined index: SERVER_PORT in /home/restofra/public_html/wp-content/plugins/ajax-search-pro/functions.php on line 184
It is somehow related to :
function wd_current_page_url() { $pageURL = 'http'; if( isset($_SERVER["HTTPS"]) ) { if ($_SERVER["HTTPS"] == "on") {$pageURL .= "s";} } $pageURL .= "://"; if ($_SERVER["SERVER_PORT"] != "80") { $pageURL .= $_SERVER["SERVER_NAME"].":".$_SERVER["SERVER_PORT"].$_SERVER["REQUEST_URI"]; } else { $pageURL .= $_SERVER["SERVER_NAME"].$_SERVER["REQUEST_URI"]; } return $pageURL; }
Could you please let me know how to fix this?
Thank you.
December 30, 2015 at 1:21 pm #7197Hi!
I’ve googled a bit about this issue, and most likely there might have been a change on your hosting – either IPv6 address or something similar. This code has been around before the update, you just probably didn’t get notices before that.
Can you please try to replace the code with this modified version of this function?
function wd_current_page_url() { $pageURL = 'http'; $port = !empty($_SERVER["SERVER_PORT"]) ? $_SERVER["SERVER_PORT"] : 80; $server_name = !empty($_SERVER["SERVER_NAME"]) ? $_SERVER["SERVER_NAME"] : ""; $server_name = empty($server_name) && !empty($_SERVER['HTTP_HOST']) ? $_SERVER['HTTP_HOST'] : $server_name; if( isset($_SERVER["HTTPS"]) ) { if ($_SERVER["HTTPS"] == "on") {$pageURL .= "s";} } $pageURL .= "://"; if ($port != "80") { $pageURL .= $server_name.":".$port.$_SERVER["REQUEST_URI"]; } else { $pageURL .= $server_name.$_SERVER["REQUEST_URI"]; } return $pageURL; }
let me know if you see any notices with the change.
Best,
Ernest Marcinko
If you like my products, don't forget to rate them on codecanyon :)
January 10, 2016 at 8:30 pm #7276@Ernest
Thank you it fixes the issue !
Cheers,
J.
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